upravte zadané rovnice do základního tvaru ax2 + bx + c = 0
poté rozložte trojčlen na součin a určete kořeny
zadání |
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x2 – 8x = 9 |
x2 = 25 |
2x + 3 = x2 |
49 + 14x + x2 =
0 |
x2 – 10 = 8x +
10 |
x (x – 2) = 24 |
x + 1 = |
21 = -4x + x2 |
x2 = 9(x – 2) |
x2 +42 = -13x |
-x (11 – x) = -28 |
22 + 9x = x2 |
2 (20 + 3x) = x2 |
x + 2 = |
x (x – 1) = 30 |
x2 – 1 = 8 (x –
1) |
x (15 + x) = -36 |
1 = |
x2 – 16 = 7x +
2 |
x + 1 = |
= 2x – 3 |
x + 7 = |
= -4 |
= x + 4 |
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